Answer:
f(x) = ( x+2)(x-5)(x-6)
Explanation:
We can write the equation with zeros at b1,b2,b3
f(x) =a( x-b1)(x-b2)(x-b3) where a is a constant and b1 b2 b3 are the zeros
f(x) = a( x- -2)(x-5)(x-6)
f(x) = a( x+2)(x-5)(x-6)
We can choose a since we are not given any more information about the function. Let a = 1
f(x) = 1( x+2)(x-5)(x-6)
f(x) = ( x+2)(x-5)(x-6)