Answer:
CI 90% = ( 0.227 ; 0.273)
Explanation:
Information from the survey:
sample size n = 938
number of people with yes answer x = 235
proportion of people p = 235/938
p = 0.25 then q = 1 - 0.25 q = 0.75
Confidence Interval 90 % .
CI 90% = ( p ± SE )
CI 90% = ( p ± z(c)*√(p*q)/n)
CI 90 % then significance level is α = 10 % α/2 = 5%
α/2 = 0.05 we find in z-table z (c) = 1.64
√(p*q)/n = √0.25*0.75/938
√(p*q)/n = √0.000199
√(p*q)/n = 0.014
CI 90% = ( p ± z(c)*√(p*q)/n)
CI 90% = ( 0.25 ± 1.64*0.014)
CI 90% = ( 0.25 ± 0.023 )
CI 90% = ( 0.227 ; 0.273)