2 Answers

Diederikh · Answer 1 · 2022-03-27T16:38:40+0000

Answer:

d. End product is that product with a ketone and carboxylic acid.

Step-by-step explanation:

${ \sf{NaBH_(4) : }}$

Sodium borohydride is a reducing agent, it reduces the ketone to a primary alcohol.

${ \sf{H _(2) O \: and \: H {}^( + ) }}$

Then acidified water is an oxidising mixture which reverses the reduction reaction.

Please log in or register to add a comment.