Question

Find the area enclosed in the graph of
x² + y² 16x + 32y.

Answer 1

3

256

sq.units

Explanation:

Both parabolas cut each other at (0,0) and (16,16)

Area enclosed by these parabolas

=∫

0

16

4

x

dx−∫

0

16

16

x

2

dx

=[

3

2×4×x

3/2

]

0

16

−[

16×3

x

3

]

0

16

=

3

2×4

4

−

3

4

4

=

3

256

sq. units