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0 votes
Find the area enclosed in the graph of
x² + y² 16x + 32y.

User Cenza
by
8.4k points

1 Answer

2 votes

Answer:

3

256

sq.units

Explanation:

Both parabolas cut each other at (0,0) and (16,16)

Area enclosed by these parabolas

=∫

0

16

4

x

dx−∫

0

16

16

x

2

dx

=[

3

2×4×x

3/2

]

0

16

−[

16×3

x

3

]

0

16

=

3

2×4

4

3

4

4

=

3

256

sq. units

User Mitaksh Gupta
by
7.6k points

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