Question

A motorcycle starts from rest and gains a velocity of 40m/s in 8 seconds. Find (i) acceleration and (ii) distance travelled by the motorcycle.​

Answer 1

• Initial velocity (u) = 0 m/s

• Final velocity (v) = 40 m/s

• time (t) = 8s

Acceleration :

`\implies \sf a = (\Delta v)/( t) \\`

`\implies \sf a = (v - u)/( t)`

`\implies \sf a = (40 - 0)/( 8)`

`\implies \sf a = (40)/( 8)`

`\implies \bf a = 5 \: {ms}^( - 2)`

• Distance travelled by the motorcycle:

`\longrightarrow \sf {v}^(2) - {u}^(2) = 2as \\`

`\longrightarrow \sf {(40)}^(2) - {(0)}^(2) = 2 *5 * s \\`

`\longrightarrow \sf 1600 = 10s`

`\longrightarrow \sf s = (1600)/(10)`

`\longrightarrow \bf s = 160 \: m`