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Pls help me not fail

Pls help me not fail-example-1
User Henry Zhu
by
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1 Answer

1 vote

Answer:

D

Explanation:

Using the Cosine rule to find AC

AC² = BC² + AB² - (2 × BC × AB × cosB )

= 18² + 12² - ( 2 × 18 × 12 × cos75° )

= 324 + 144 - 432cos75°

= 468 - 111.8

= 356.2 ( take the square root of both sides )

AC =
√(356.2) ≈ 18.9

-----------------------------------------

Using the Sine rule to find ∠ A


(18)/(sinA) =
(18.9)/(sin75) ( cross- multiply )

18.9 sinA = 18 sin75° ( divide both sides by 18.9 )

sinA =
(18sin75)/(18.9) , then

∠ A =
sin^(-1) (
(18sin75)/(18.9) ) ≈ 66.9°

User NehaG
by
4.8k points