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A chemist determines by measurements that moles of bromine liquid participate in a chemical reaction. Calculate the mass of bromine liquid that participates. Round your answer to significant digits.

User FadelMS
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1 Answer

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Answer:

5.20 grams of Br₂

Step-by-step explanation:

From our previous knowledge;

We understand that:

The number of moles of a given element = mass of the element divided by its molar mass.

Mathematically:


\mathbf{no \ of \ moles =( mass)/( molar \ mass)}

From the given information, let's assume that the 0.065 moles of liquid -bromine partake in the reaction.

From the periodic table, the molar mass of Bromine is = 79.9 g/mol

As such, the mass of liquid that partakes is calculated as:

0.065 mol = mass/ 79.9 g/mol

mass = 0.065 mol × 79.9 g/mol

mass of liquid that partakes in the reaction = 5.20 grams of Br₂

User Ge
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