1 Answer

SmootQ · Answer 1 · 2022-08-23T11:10:00+0000

Complete Question

Complete Question is attached below

Answer:

P=1124.2ibf

Step-by-step explanation:

From the question we are told that:

Diameter
d=1.2in

Allowable Normal stress
$\sigma=27.5ksi=27.5 * 10^3 psi$

Generally the equation for Bending Stress is mathematically given by

$\phi= (32M)/( \pi d^3)$

$\phi= {32 * 4 P}{\pi * 1.2^3}$

$\phi=23.58 psi$

Generally the equation for Direct Normal Stress is mathematically given by

$\sigma'=(4P)/( \phi * 1.2^2)$

$\sigma'= 0.88P psi$

Therefore

Total Normal stress

$\sigma_T=23.58 + 0.88$

$\sigma_T=24.46P$

Generally the equation for Allowable Stress is mathematically given by

$\sigma=\sigma_T P$

$P=(\sigma)/(\sigma_T)$

P=(27.5 * 10^3)/(24.46P)

P=1124.2ibf

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