Question

A 2kg rock is at the edge of a cliff 20m above the surface of a lake. It comes loose and falls. Half way down it is falling at 14 m/s. What is its Kinetic Energy at the half way point?

Please show work!

Answer 1

196 Joules

Step-by-step explanation:

kinetic energy = 1/2 * mass * velocity²

Given:

• mass: 2 kg

• velocity: 14 m/s

using formulae:

`\rightarrow \sf kinetic \ energy = (1)/(2) * 2 * 14^2`

`\rightarrow \sf kinetic \ energy = 196 \ J`