Question

b. The stream of water flowing through a hole at depth h = 10 cm in a tank holding water to height H = 40 cm. . 3 At what distance x does the stream strike the floor?​

Answer 1

The stream of water will strike the floor directly below the hole, at a horizontal distance x = 0 m.

Step-by-step explanation:

To determine the distance at which the stream of water strikes the floor, we can use the principles of projectile motion. The stream of water can be treated as a projectile.

First, we need to find the initial velocity of the water when it leaves the hole. We can use Torricelli's equation, which states that the velocity of a fluid escaping from a hole is given by:

v = sqrt(2gh)

Where v is the velocity, g is the acceleration due to gravity (9.8 m/s²), and h is the depth of the hole (10 cm = 0.1 m).

Once we have the initial velocity, we can use the equations of projectile motion to find the horizontal distance x at which the stream strikes the floor. This can be calculated using the equation:

x = (v^2 * sin(2θ)) / g

Where θ is the angle at which the stream is projected. Since the stream emerges straight down, the angle θ is 90°, and sin(2θ) = sin(180°) = 0.

Therefore, the stream of water will strike the floor directly below the hole, at a horizontal distance x = 0 m.

Answer 2

34.64 cm

Step-by-step explanation:

Given that:

The depth of the hole h = 10 cm

height of the water holding in the tank H = 40 cm

For a stream of flowing water, the distance (x) at which the stream strikes the floor can be computed by using the formula;

`x = 2 √(h(H-h))`

`x = 2 √(10(40-10))`

`x = 2 √(10(30))`

`x = 2 √(300)`

`x = 2 * 17.32`

x = 34.64 cm