Question

IF a and bare roots of 3x² - 6x + 2=0 ,then find. a, a-b​

Answer 1

a is 1.58 and b is 0.42

Explanation:

`{ \sf{3 {x}^(2) - 6x + 2 = 0 }} \\ { \sf{x = \frac{ - b± \sqrt{ {b}^(2) - 4ac} }{2a} }} \\ \\ { \sf{x = \frac{ - ( - 6)± \sqrt{ {( - 6)}^(2) - (4 * 3 * 2) } }{(2 * 3)} }} \\ \\ { \sf{x = (6± √(12) )/(6) }} \\ \\ { \sf{x = 1.58 \: and \: 0.42}}`