Question

Find the equation of a line that is perpendicular to x+y=8 and passes through the point (8, 10).

Answer 1

y-y1=m(x-x1)

y-10=8(x-8)

y-10=8x-64

y-10+64-8x

y+54-8x

y-8x+54

Answer 2

Y = -x + 2

Explanation:

y = -x + 8

y = 1x + b

10 = 8 + b

b = 2