A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from the center of the wire. (in Nm2/C, keep 3 signif…

Question

asked Jun 8, 2022 18.2k views

1 Answer

Eprst · Answer 1 · 2022-06-13T09:11:57+0000

Answer:

E=35921.96N/C

Step-by-step explanation:

From the question we are told that:

Radius
r=0.321mm

Charge Density
$\mu=0.100$

Distance
d= 5.00 cm

Generally the equation for electric field is mathematically given by

$E=(mu)/(2\pi E_0r)$

E=(0.100*10^(-6))/(2*3.142*8.86*10^(-12)*5*10^(-2))

E=35921.96N/C