Question

A long copper wire of radius 0.321 mm has a linear charge density of 0.100 μC/m. Find the electric field at a point 5.00 cm from the center of the wire. (in Nm2/C, keep 3 significant figures)

Answer 1

`E=35921.96N/C`

Step-by-step explanation:

From the question we are told that:

Radius
`r=0.321mm`

Charge Density
`\mu=0.100`

Distance
`d= 5.00 cm`

Generally the equation for electric field is mathematically given by

`E=(mu)/(2\pi E_0r)`

`E=(0.100*10^(-6))/(2*3.142*8.86*10^(-12)*5*10^(-2))`

`E=35921.96N/C`