Question

Quadrilateral ABCD will be dilated about the origin by a scale factor of 1/3 and then reflected across the y-axis.

Answer 1

See explanation

Explanation:

The coordinate of ABCD is not given; So, I will solve using general coordinates (x,y).

First, ABCD is dilated by 1/3.

The rule is:

`(x,y) \to (1)/(3)(x,y)`

This gives

`(x,y) \to ((x)/(3),(y)/(3))`

Next, it is reflected across y-axis.

The rule is:

`(x,y) \to (-x,y)`

So, we have:

`((x)/(3),(y)/(3)) \to (-(x)/(3),(y)/(3))`

So, the complete transformation is:

`(x,y) \to ((x)/(3),(y)/(3)) \to (-(x)/(3),(y)/(3))`

Assume that:

`A = (1,3)`

The transformation will be:

`A' = (-(1)/(3),(3)/(3))`

`A' = (-(1)/(3),1)`