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X^{2}-7x-25=0 to the nearest tenth

2 Answers

4 votes

For this just use the quadratic formula to find the zeros. In this case, you get 7 +/- square root 149 over 2. Which gives you -2.6 and 9.6.

User Aaron Bramson
by
7.6k points
5 votes

Answer:

x = 9.6

x = - 2.6

Explanation:


x=\frac{-b±\sqrt{b^(2)-4ac } }{2a}

Ignore the before the ± it wouldn't let me type it correctly.

x² - 7x - 25 = 0

a = 1

b = - 7

c = - 25


x=\frac{-(-7)±\sqrt{-7^(2)-4((1)(-25)) } }{2(1)}


x=(7±√(49-4((1)(-25)) ) )/(2(1))


x=(7±√(49+100 ) )/(2(1))


x=(7±√(149 ) )/(2)


x=(7±12.2)/(2)

Two separate equations


x=(7+12.2)/(2)


x=(7-12.2)/(2)


x=(7+12.2)/(2)


x=(19.2)/(2)

x = 9.6


x=(7-12.2)/(2)


x=(-5.2)/(2)

x = - 2.6

User Meeker
by
9.8k points

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