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A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the lower end of a slender 23-lb bar of length L = 30 in. Knowing that h = 12 in. and that the bar is initially at rest. Determine the angular velocity of the bar immediately after the bullet becomes embedded.

User Malitta N
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Answer: hello attached below is the missing image the slender weight is different from what is in the question here so I worked with 23-Ib as requested in the question

answer

≈ 12.17 Rad/sec

Step-by-step explanation:

weight of bullet ( Wb ) = 0.08 Ib

horizontal velocity = 1800 ft/s

Slender(Wr) = 23-Ib bar with

length ( L ) = 30

h = 12 inches

Vro = 0

Calculate the angular velocity of the bar immediately after the bullet becomes embedded

attached below is a detailed solution

6.708 = ( 0.05011 + 0.5011 ) w'

w' = 6.708 / 0.55121 ≈ 12.17 Rad/sec

A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the-example-1
A bullet weighing 0.08 lb is fired with a horizontal velocity of 1800 ft/s into the-example-2
User SandTh
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