Question

Ivan caught a total of 7 2/5 pounds of fish one day. Of the fish caught, 4 5/8 pounds were sea bass and the rest were mackerel. He gave away 1 7/8 pounds of mackerel. How many pounds of mackerel did he have left.

Answer 1

The amount of Mackerel left is 9/10.

Explanation:

total fish = 7 2/5 pounds

sea bass = 4 5/8

The amount of mackerel =

`7(2)/(5)-4(5)/(8)\\\\=(37)/(5)-(37)/(8)\\\\=(296-185)/(40)\\\\=2 (31)/(40)`

Mackerel left =

`2 (31)/(40)-1(7)/(8)\\\\= (111)/(40)-(15)/(8)\\\\=(111-75)/(40)\\\\=(36)/(40)\\\\=(9)/(10)`

Answer 2

Given:

Total fish (Sea bass and mackerel) =
`7(2)/(5)` pounds

Sea bass =
`4(5)/(8)` pounds

He gave away
`1(7)/(8)` pounds of mackerel.

To find:

The remaining mackerel.

Solution:

We know that,

Mackerel = Total fish - Sea bass

`\text{Mackerel}=7(2)/(5)-4(5)/(8)`

`\text{Mackerel}=(37)/(5)-(37)/(8)`

`\text{Mackerel}=(296-185)/(40)`

`\text{Mackerel}=(111)/(40)`

He gave away
`1(7)/(8)` pounds of mackerel. So, the remaining mackerel is:

`\text{Remaining Mackerel}=(111)/(40)-1(7)/(8)`

`\text{Remaining Mackerel}=(111)/(40)-(15)/(8)`

`\text{Remaining Mackerel}=(111-75)/(40)`

`\text{Remaining Mackerel}=(36)/(40)`

`\text{Remaining Mackerel}=(9)/(10)`

Therefore, the remaining Mackerel is
`(9)/(10)` pounds or 0.9 pounds.