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Ivan caught a total of 7 2/5 pounds of fish one day. Of the fish caught, 4 5/8 pounds were sea bass and the rest were mackerel. He gave away 1 7/8 pounds of mackerel. How many pounds of mackerel did he have left.

User Dinya
by
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2 Answers

1 vote

Answer:

The amount of Mackerel left is 9/10.

Explanation:

total fish = 7 2/5 pounds

sea bass = 4 5/8

The amount of mackerel =


7(2)/(5)-4(5)/(8)\\\\=(37)/(5)-(37)/(8)\\\\=(296-185)/(40)\\\\=2 (31)/(40)

Mackerel left =


2 (31)/(40)-1(7)/(8)\\\\= (111)/(40)-(15)/(8)\\\\=(111-75)/(40)\\\\=(36)/(40)\\\\=(9)/(10)

User Ishvar Kikani
by
3.9k points
3 votes

Given:

Total fish (Sea bass and mackerel) =
7(2)/(5) pounds

Sea bass =
4(5)/(8) pounds

He gave away
1(7)/(8) pounds of mackerel.

To find:

The remaining mackerel.

Solution:

We know that,

Mackerel = Total fish - Sea bass


\text{Mackerel}=7(2)/(5)-4(5)/(8)


\text{Mackerel}=(37)/(5)-(37)/(8)


\text{Mackerel}=(296-185)/(40)


\text{Mackerel}=(111)/(40)

He gave away
1(7)/(8) pounds of mackerel. So, the remaining mackerel is:


\text{Remaining Mackerel}=(111)/(40)-1(7)/(8)


\text{Remaining Mackerel}=(111)/(40)-(15)/(8)


\text{Remaining Mackerel}=(111-75)/(40)


\text{Remaining Mackerel}=(36)/(40)


\text{Remaining Mackerel}=(9)/(10)

Therefore, the remaining Mackerel is
(9)/(10) pounds or 0.9 pounds.

User Kimm
by
3.5k points