Question

Analysis of an ore of calcium shows that it contains 13.61 g calcium and 21.77 g oxygen in a 46.28-g sample. Calculate the percent composition of this compound.

Answer 1

The percent composition of the ore of calcium is approximately 38.47% calcium and 61.53% oxygen.

Step-by-step explanation:

To calculate the percent composition of the ore, we need to calculate the mass of calcium and oxygen in the sample. The mass of 13.61 g calcium and 21.77 g oxygen combine to give a total mass of 35.38 g for the two elements. To find the percent composition, we divide the mass of each element by the total mass and multiply by 100.

Percent composition of calcium = (mass of calcium / total mass) * 100 = (13.61 g / 35.38 g) * 100 ≈ 38.47%

Percent composition of oxygen = (mass of oxygen / total mass) * 100 = (21.77 g / 35.38 g) * 100 ≈ 61.53%

Answer 2

29.41% of Calcium and 47.04% of Oxygen

Step-by-step explanation:

The percent composition of an atom in a molecule is defined as 100 times the ratio between the mass of the atom and the mass of the molecule.

The mass of the molecule of the problem (Ore) is 46.28g. That means the percent composition of Calcium is:

13.61g / 46.28g * 100 = 29.41% of Calcium

And percent composition of Oxygen is:

21.77g / 46.28g * 100 = 47.04% of Oxygen