Answer:
v = 4.4 x 10⁷ m/s
Step-by-step explanation:
The kinetic energy of the electrons will be equal to the energy supplied by the electric voltage:
Kinetic Energy = Electric Energy
![(1)/(2)mv^2 = eV](https://img.qammunity.org/2022/formulas/physics/college/hcoantif8vu2nw7kpn5dbddl5siusd0ops.png)
where,
m = mass of electron = 9.1 x 10⁻³¹ kg
v = speed of electron = ?
e = charge on electron = 1.6 x 10⁻¹⁹ C
V =Voltage = 55 kV = 55000 V
Therefore,
![(1)/(2)(9.1\ x\ 10^(-31)\ kg)(v)^2 = (1.6\ x\ 10^(-19)\ C)(55000\ V)\\\\v^2 = ((2)(8.8\ x\ 10^(-16)\ J))/(9.1\ x\ 10^(-31)\ kg)\\\\v = \sqrt{19.34\ x\ 10^(14)\ m^2/s^2}](https://img.qammunity.org/2022/formulas/physics/college/z8m7x1wgk33b8cib5y28fxz0mlns0pmk6e.png)
v = 4.4 x 10⁷ m/s