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A 2 nC point charge is embedded at the center of a nonconducting sphere of radius = 4.8 cm which has a charge of 1 nC distributed uniformly throughout its volume. What is the magnitude of the electric field at a point that is 2.4 cm from the center of the sphere? Write your answer in terms of kN/C.

User Jenny Mok
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1 Answer

3 votes

Answer:
3.32* 10^4\ kN/C

Step-by-step explanation:

Given

Charge at the center of the sphere is
q=2\ nC

Charge distributed over the entire sphere
Q=1\ nC

Radius of sphere
r=4.8\ cm

Using Guass law


\Rightarrow \oint \vec{E}\cdot \vec{dA}=(q_(enc))/(\epsilon_o)\\\\\Rightarrow E\cdot 4\pi r^2=(1)/(\epsilon)(q+(Q)/(4\pi R^2)* 4\pi r^2)\\\\\Rightarrow E\cdot 4\pi r^2=(1)/(\epsilon)(q+Q(r^2)/(R^2))\\\\\Rightarrow E\cdot (2.4* 10^(-2))^2=9* 10^9(2+1\cdot (1)/(4))* 10^(-9)\\\\\Rightarrow E=3.32* 10^4\ kN/C

User Chandu Komati
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5.6k points