Question

The thermal efficiency (in %) of a system that undergoes a power cycle while receiving 1000 kJ of energy by heat transfer from a hot reservoir at 1000 K and discharging 500 kJ of energy by heat transfer to a cold reservoir at 400 K is:

Answer 1

η = 0.5 = 50%

Step-by-step explanation:

The efficiency of the power cycle is given by the following formula:

`\eta = (W)/(Q_1)\\\\\eta = (Q_1-Q_2)/(Q_1)`

where,

where,

η = efficiency = ?

Q₁ = heat received from hot reservoir = 1000 KJ

Q₂ = heat discharged to cold reservoir = 500 KJ

Therefore,

`\eta = (1000\ KJ-500\ KJ)/(1000\ KJ)`

η = 0.5 = 50%