8.50 g of a sample of iron required just 75 cm of 3.00 M HCl to dissolve it and give a neutral solution. Calculate the % purity of the sample of iron.

My account
Edit my Profile
Private messages
My favorites

Ask a Question
Questions
Unanswered
Tags
Categories
Ask a Question

asked Dec 13, 2022 109k views

0 votes

8.50 g of a sample of iron required just 75 cm of 3.00 M HCl to dissolve it and give a neutral solution. Calculate the % purity of the sample of iron.

Chemistry
high-school

Ramiz asked

by Ramiz

4.1k points

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

4 votes

Answer:

Step-by-step explanation:

2HCl +Fe =FeCl2+H2

nHCl=0.225

nFe=0.225/2

H=74.12%

CatalystNZ answered Dec 18, 2022

by CatalystNZ

4.6k points

0 Comments

Please log in or register to add a comment.

Ask a Question

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.5m questions

5.8m answers

0 Comments

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

0 Comments

Please log in or register to add a comment.

Other Questions