8.50 g of a sample of iron required just 75 cm of 3.00 M HCl to dissolve it and give a neutral solution. Calculate the % purity of the sample of iron.

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asked Dec 13, 2022 109k views

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8.50 g of a sample of iron required just 75 cm of 3.00 M HCl to dissolve it and give a neutral solution. Calculate the % purity of the sample of iron.

Chemistry
high-school

Ramiz asked

by Ramiz

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Answer:

Step-by-step explanation:

2HCl +Fe =FeCl2+H2

nHCl=0.225

nFe=0.225/2

H=74.12%

CatalystNZ answered Dec 18, 2022

by CatalystNZ

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