1 Answer

Dimitris Siakavelis · Answer 1 · 2023-11-25T20:21:20+0000

Solution:

$\text G\text i\text v\text e\text n\ \text e\text x\text p\text r\text e\text s\text s\text i\text o\text n: 20x^(3) + 34x^(2) + 6x$

Step-1: Find the GCF of the terms.

$20x^(3) \ \ \ = \ \ \ 2 * 2 * 5 * x * x * x \\34x^(2) \ \ \ = \ \ \ 2 * 17 * x * x \\ 6x \ \ \ \ \ \ = \ \ \ 2 * 3 * x$

GCF = 2x

Step-2: Factor the expression using the GCF.

$20x^(3) + 34x^(2) + 6x \\\\ {2x(10x^(2) + 17x + 3)}$

Step-3: Further factorize.

${2x(10x^(2) + 17x + 3)}$

2x(2x + 3)(5x + 1)

Thus, the factorized expression is
2x(2x + 3)(5x + 1) .

Please log in or register to add a comment.