Question

Three tennis balls that fit in cylindrical tennis ball cane. If each ball is 14 inches in diameter, what is the volume of air left between the balls and the cane​

Answer 1

Given:

Diameter of the tennis ball = 14 inches.

Three tennis balls are fit in a cylindrical tennis ball cane.

To find:

The volume of air left between the balls and the cane​.

Solution:

Diameter of the tennis ball = 14 inches.

Radius of the tennis ball = 7 inches

Radius of tennis ball is equal to radius of cane. So,

Radius of the cane = 7 inches

Height of cane is:

`3* 14=42` inches

Volume of a ball is:

`V_1=(4)/(3)\pi r^3`

Where, r is the radius of the ball.

So, the volume of 3 ball is:

`V_2=3* V_1`

`V_2=3* (4)/(3)* (22)/(7)* (7)^3`

`V_2=4312`

Volume of the cane is:

`V_3=\pi r^2h`

Where, r is the radius of the cane and h is the height of the cane.

`V_3=(22)/(7)* (7)^2* 42`

`V_3=6468`

Now, the volume of air left between the balls and the cane​ is:

`V=V_3-V_2`

`V=6468-4312`

`V=2156`

Therefore, the volume of air left between the balls and the cane​ is 2156 cubic inches.