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Refrigerant 134a enters an insulated compressor operating at steady state as saturated vapor at 2208C with a mass flow rate of 1.2 kg/s. Refrigerant exits at 7 bar, 708C. Changes in kinetic and potential energy from inlet to exit can be ignored. Determine (a) the volumetric flow rates at the inlet and exit, each in m3 /s, and (b) the power input to the compressor, in kW.'

User KKM
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1 Answer

2 votes

Answer:

a)
V_1=4.88m^2/s


V_2=4.88m^2/s

b)
P=-119.18kW

Step-by-step explanation:

From the question we are told that:

Steady State Saturated vapor
T_1= -20C=>253k

Mass Flow rate
M=1.2kg/s

Exit Pressure
P_2=7bar

Exit Temperature
T_2=70C=>373k

From Refrigerant 134a Properties


T_1= -20C =>P_1=1.399 bar

Generally the equation for Volumetric Flow rate is mathematically given by

For Inlet


V_1=m(RT_1)/(P_1)


V_1=m(8314*253)/(1.399*10^3)


V_1=18.97m^2/s

For outlet


V_2=m(RT_2)/(P_2)


V_2=1.2*(8314*343)/(7*10^3)


V_2=4.88m^2/s

b)

Generally the equation for Steady state mass and energy equation is mathematically given by


P=m(h_1-h_2)

From Refrigerant 134a Properties


T_1= -20C =>h_1=24.76kJ/kg


T_2= 70C =>h_2=124.08kJ/kg

Therefore


P=1.2(12.76-124.08)


P=-119.18kW

Therefore

Power input into the compressor is


P=-119.18kW

User Elreeda
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