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Solve for x and y
Y=2/3x-2 y=-x+3

User Lingster
by
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1 Answer

3 votes

Answer:


y=0,\:x=3

Explanation:


\begin{bmatrix}y=(2)/(3)x-2\\ y=-x+3\end{bmatrix}


\mathrm{Substitute\:}y=-x+3


\begin{bmatrix}-x+3=(2)/(3)x-2\end{bmatrix}

Isolate x for -x+3=2/3x-2: x=3


\mathrm{For\:}y=-x+3


\mathrm{Substitute\:}x=3


y=-3+3


\mathrm{Simplify}


y=0


\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}


y=0,\:x=3

User Flymike
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