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Ross walked 3 m east and 6 m north. How far is he from the starting point

User Dechov
by
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2 Answers

2 votes

Answer:

3 sqrt(5) meters

Explanation:

This is a right triangle so we can use the Pythagorean theorem.

a^2 +b^2 = c^2 where a and b are the legs and c is the hypotenuse

3^2+6^2 = c^2

9+36 = c^2

45 = c^2

Taking the square root

sqrt(45) = sqrt(c^2)

sqrt(9*5) = c

sqrt(9) sqrt(5) =c

3sqrt(5) = c

Ross walked 3 m east and 6 m north. How far is he from the starting point-example-1
User Jick Lee
by
8.3k points
7 votes


\boxed{\large{\bold{\blue{ANSWER~:) }}}}

Given:-

  • Ross walked 3 m east and 6 m north.

Find:-

  • How far is she from the starting point?

solution:-

Ross walked 3 m east and 6 m north.

so her path is a right angle triangle path.

we know that,

in a right angle triangle, According to the Pythagorean theorom,


\boxed{\sf{l^2+b^2=h^2 }}

where

  • l= legs
  • b=base
  • h=hypotenuse

According to the question,


  • \sf{3^2+6^2=f^2 }


  • \sf{9+36=f^2 }


  • \sf{ f^2=45 }


  • \sf{f=√(45) }


  • \sf{f=3√(5) }

Therefore:-

he is
\sf{3√(5) } far from the starting point

Ross walked 3 m east and 6 m north. How far is he from the starting point-example-1
User Lionel Parreaux
by
8.4k points

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