Question

A slab-milling operation is performed on a 0.7 m long, 30 mm-wide cast-iron block with a feed of 0.25 mm/tooth and depth of cut of 3 mm. The cutter has a diameter of 75 mm, has 8 cutting teeth, and rotates at 200 rpm. Calculate the cutting time and material removal rate.

Answer 1

a)
`T_m=1.787min`

b)
`MRR=35259.7mm^3/min`

Step-by-step explanation:

From the question we are told that:

Cast-iron block Dimension:

Length
`l=0.7m=>700mm`

Width
`w=30mm`

Feed
`F=0.25mm/tooth`

Depth
`dp=3mm`

Diameter
`d=75mm`

Number of cutting teeth
`n=8`

Rotation speed
`N=200rpm`

Generally the equation for Approach is mathematically given by

`x=√(Dd-d^2)`

`X=√(75*3-3^2)`

`X=14.69mm`

Therefore

Effective length is given as

`L_e=Approach +object Length`

`L_e=700+14.69`

`L_e=714.69mm`

a)

Generally the equation for Machine Time is mathematically given by

`T_m=(L_e)/(F_m)`

Where

`F_m=F*n*N`

`F_m=0.25*8*200`

`F_m=400`

Therefore

`T_m=(714.69)/(400)`

`T_m=1.787min`

b)

Generally the equation for Material Removal Rate. is mathematically given by

`MRR=(L*B*d)/(t_m)`

`MRR=(700*30*3)/(1.787)`

`MRR=35259.7mm^3/min`