Question

Block A hangs by a cord from spring balance D and is submerged in a liquid C contained in beaker B. The mass of the beaker is 1.20 kg; the mass of the liquid is 1.85 kg. Balance D reads 3.10 kg and balance E reads 7.50 kg. The volume of block A is 4.15 × 10−3 m3.

a) What is the density of the liquid?
b) What will the balance D read if block A is pulled up out of the liquid?
c) What will the balance E read if block A is pulled up out of the liquid?

Answer 1

a)
`m_e= 3.05 Kg`

b)
`\rho=1072.3kg/m^3`

c)
`m_e= 3.05 Kg`

Step-by-step explanation:

From the question we are told that:

Beaker Mass
`m_b=1.20`

Liquid Mass
`m_l=1.85`

Balance D:

Mass
`m_d=3.10`

Balance E:

Mass
`m_e=7.50`

Volume
`v=4.15*10^(-3)m^3`

a)

Generally the equation for Liquid's density is mathematically given by

`m_e=m_b+m_l+(\rho*v)`

`\rho=(7.50-(1.2+1.85))/(4.15*10^(-3))`

`\rho=1072.3kg/m^3`

b)

Generally the equation for D's Reading at A pulled is mathematically given by

m_d = mass of block - mass of liquid displaced

`m_d=m- (\rho *v )`

`m=3.10+ (1072.30 *4.15*10^(-3)m^3 )`

`m=18.10kg`

c)

Generally the equation for E's Reading at A pulled is mathematically given by

`m_e=m_b+m_l`

`m_e = 1.20 + 1.85`

`m_e= 3.05 Kg`