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Using the formula do you sound level and disciples are use the intensity of the sound you're measuring. Set an alarm to normal conversation has an intensity of 3.2×10 to the -6

User WYi
by
8.0k points

1 Answer

4 votes

Answer:

65.1 decibels

Explanation:

Given


I = 3.2 * 10^(-6) --- intensity

Required

Determine the sound level

This is calculated using:


B = 10\log((I)/(I_o))

Where:


I_o = 1 * 10^(-12)

So, we have:


B = 10\log((3.2 * 10^(-6))/(1 * 10^(-12)))

Apply law of indices


B = 10\log((3.2 * 10^(-6+12))/(1))


B = 10\log(3.2 * 10^(6))

Using a calculator, we have:


B = 10*6.51


B = 65.1

User Aklesh Singh
by
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