Question

Consider the reaction “2 SO2 (g) + O2 (g) = 2 SO3 was 0.175 M. After 50 s the concentration of SO2 Date: (g)”. Initial concentration of SO2 (g) (g) became 0.0500 M. Calculate rate of the reaction

Answer 1

The answer is "
`1.25 * 10^(-3) \ (m)/(s)`"

Step-by-step explanation:

Calculating the rate of the equation:

`=-(1)/(2) (\Delta [SO_2])/(\Delta t) =-(\Delta [O_2])/(\Delta t)= +(1)/(2) (\Delta [SO_3])/(\Delta t)\\\\=(\Delta [SO_2])/(\Delta t)=(0.0500-0.175\ M)/(505)= -2.5 * 10^(-3) \ (m)/(s)\\\\`

Rate:

`=(-2.5 * 10^(-3))/(2)=1.25 * 10^(-3) \ (m)/(s)`