Question

A solution contains only sucrose and water. If the mole fraction of sucrose is 0.0558, determine the molality of sucrose.

Answer 1

The correct solution is "3.28 m".

Step-by-step explanation:

According to the question,

Mol fraction of solvent,

= 0.0558

Molar mass of water,

= 18 g/mol

Mol of H₂O in 1000 g water,

= 55.55 mol

Now,

Let the mol of solute will be "x mol".

Total mol in solution will be "55.55 + x".

As we know,

⇒ The mol fraction of solvent =
`(x)/(55.55+x)`

`0.0558=(x)/(55.55+x)`

`x=0.0558[55.55+x]`

`x=3.09969+0.0558x`

`x-0.0558x=3.09969`

`x=(3.09969)/(0.9442)`

`=3.38 \ m`