Question

1. A plane flying a triangular patter flies 150 km[N], then 400 km(E). What is the total displacement of the

plane after these two legs? {4}
2. Ken and Susie are standing together. Ken walks 10 m (N) and then 15 m [W]. Susie walks 25 m [E] and
then 30 m [S]. What is the displacement from Ken to Susie? {5}
3. Students are performing an experiment for their physics class and are testing their predictions for
projectile motion. They set up a system so that a beanbag is launched horizontally off one of their
desks with an initial speed of 4.2 m/s. They measure the height of the desk to be 1.3 m.
a. What is the time of flight for the beanbag? {3}
b. What is the range for the beanbag? {2}
4. A historical society is testing an old cannon on the top of an old fort that has rusted and can only be
fired horizontally. They perform a few test fires of the cannon and measure the time of flight to be
3.78 s. How high is the hill? {3}

Answer 1

The total displacement of the plane after flying 150 km North and 400 km East is approximately 427 km.

Step-by-step explanation:

The displacement of an object can be determined by adding the individual displacements in each direction. In the first question, the plane flies 150 km North and then 400 km East. The final displacement can be calculated using the Pythagorean theorem:

Displacement = √((150 km)^2 + (400 km)^2) = sqrt(22500 km^2 + 160000 km^2) = sqrt(182500 km^2) ≈ 427 km

Therefore, the total displacement of the plane is approximately 427 km.