Question

Iff a projectile has a maximum range of 40 metres , find its speed of projection . (
`g = 10ms^-^2`)

.
`0.5 ms^-^1\\2ms^-^1\\\\4ms^-^1\\\\20ms^-^1\\\\400ms^-^1`

Answer 1

its speed of projection is 20 ms^(-1)

Answer:

Solution given:

maximum range=40m

u²sin90°/g=40

u²*sin90°/10=40

u²=40*10

u=
`√(400)=20m/s`