Iff a projectile has a maximum range of 40 metres , find its speed of projection . (g = 10ms^-^2) .0.5 ms^-^1\\2ms^-^1\\\\4ms^-^1\\\\20ms^-^1\\\\400ms^-^1

asked Oct 16, 2022 177k views

1 vote

Iff a projectile has a maximum range of 40 metres , find its speed of projection . (
g = 10ms^-^2

)

.
$0.5 ms^-^1\\2ms^-^1\\\\4ms^-^1\\\\20ms^-^1\\\\400ms^-^1$

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4 votes

its speed of projection is 20 ms^(-1)

Answer:

Solution given:

maximum range=40m

u²sin90°/g=40

u²*sin90°/10=40

u²=40*10

u=
√(400)=20m/s

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