Prove algebraically that n^2-2-(n-2)^2 is always even

asked Feb 3, 2022 42.9k views

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Explanation:

Nirrek answered Feb 5, 2022

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Answer:

It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)

Explanation:

${n}^(2) - 2 - ( {n}^(2) + 4 - 4n) = \\ {n}^(2) - 2 - {n}^(2) - 4 + 4n = \\ 4n - 6 = 2(2n - 3)$

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