Question

Prove algebraically that n^2-2-(n-2)^2 is always even

Answer 1

Explanation:

Answer 2

It is even because it is equal to 2(2n-3) so you can divide it by two and get (2n-3)

Explanation:

`{n}^(2) - 2 - ( {n}^(2) + 4 - 4n) = \\ {n}^(2) - 2 - {n}^(2) - 4 + 4n = \\ 4n - 6 = 2(2n - 3)`