Question

1 point
What is the slope of a line perpendicular to 3x + 4y = -2?

Answer 1

4/3

Explanation:

In slope-intercept form
`y=mx+b`,
`m` represents the slope of the line.

Let's write
`3x+4y=-2` in slope-intercept form by isolating
`y`:

`3x+4y=-2,\\4y=-3x-2,\\y=-(3)/(4)x-(1)/(2)`

Therefore, the slope of this line is
`(-3)/(4)`. To find the slope of a line perpendicular to it, multiply the reciprocal of the slope by -1 (take the negative reciprocal).

Therefore, the slope of a line perpendicular to
`3x+4y=-2` is:

`m_(perp)=-(-(4)/(3))=\boxed{(4)/(3)}`

Answer 2

4/3

Given equation :-

• 3x + 4y = -2
• 4y = -3x - 2
• y = (-3x - 2)/4
• y = -3/4 x - 1/2

Slope :-

• m = -3/4

Slope of perpendicular line :-

• m' = -(1/m )
• m' = -( 1 ÷ -3/4 )
• m' = -1 * -4/3
• m = 4/3