Find the x-intercepts y=2x^2 + 5x + 2/x^2-4x+3

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asked Jun 28, 2022 190k views

3 votes

Find the x-intercepts y=2x^2 + 5x + 2/x^2-4x+3

Mathematics
college

Nist asked

by Nist

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1 Answer

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Answer:

${ \tt{y = \frac{2 {x}^(2) + 5x + 2}{ {x}^(2) - 4x + 3 } }} \\ x - intercept : y = 0 \\ { \tt{ \frac{2 {x}^(2) + 5x + 2 }{ {x}^(2) - 4x + 3 } = 0 }} \\ \\ { \tt{2 {x}^(2) + 5x + 2 = 0}} \\ x = (1)/(2) \: \: and \: \: x = - 2$

Pranag answered Jul 4, 2022

by Pranag

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