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Hi, may someone help me with this question? Thank you!:)

“If f(x) = x^2 + 7, find f(x+2)”

2 Answers

1 vote

Answer:


f(x+2)=x^2+4x+11

Explanation:

In
f(x)=x^2+7, for all values of
x, we substitute
x (what is in the parentheses) into
x^2+7 to output a
y value.

In
f(x+2), the term
(x+2) is in the parentheses. Therefore, substitute
(x+2) for
x in
x^2+7 to find
f(x+2):


f(x+2)=(x+2)^2+7

Expand using
(a+b)^2=a^2+2ab+b^2,


f(x+2)=x^2+4x+4+7

Combine like terms:


\boxed{f(x+2)=x^2+4x+11}

User Interjay
by
7.9k points
4 votes

Answer:

=x^2 +4x+11

Explanation:

f(x) = x^2 + 7,

Replace x with x+2

f(x+2) = (x+2)^2 + 7

= (x+2)(x+2) +7

FOIL

= x^2 +2x+2x+4 +7

Combine like terms

=x^2 +4x+11

User Daniele Bernardini
by
8.1k points

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