Question

Hi, may someone help me with this question? Thank you!:)

“If f(x) = x^2 + 7, find f(x+2)”

Answer 1

`f(x+2)=x^2+4x+11`

Explanation:

In
`f(x)=x^2+7`, for all values of
`x`, we substitute
`x` (what is in the parentheses) into
`x^2+7` to output a
`y` value.

In
`f(x+2)`, the term
`(x+2)` is in the parentheses. Therefore, substitute
`(x+2)` for
`x` in
`x^2+7` to find
`f(x+2)`:

`f(x+2)=(x+2)^2+7`

Expand using
`(a+b)^2=a^2+2ab+b^2`,

`f(x+2)=x^2+4x+4+7`

Combine like terms:

`\boxed{f(x+2)=x^2+4x+11}`

Answer 2

=x^2 +4x+11

Explanation:

f(x) = x^2 + 7,

Replace x with x+2

f(x+2) = (x+2)^2 + 7

= (x+2)(x+2) +7

FOIL

= x^2 +2x+2x+4 +7

Combine like terms

=x^2 +4x+11