Question

If a gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, then what happens to the temperature of the gas?

Answer 1

If a gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, then the temperature of the gas will also double.

Step-by-step explanation:

According to Gay-Lussac's law, for a given amount of gas held at constant volume, the pressure is proportional to the absolute temperature. This means that if the gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, the temperature of the gas would also double. This happens because as the volume increases, the gas molecules have more space to move and their kinetic energy (related to temperature) increases, resulting in a higher temperature.

Answer 2

Answer: If a gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, then temperature of the gas increases twice.

Step-by-step explanation:

Charles law states that at constant pressure, the volume of a gas is directly proportional to the temperature.

That is,
`V \propto T`.

So, when a gas is pumped from a smaller container to a container that is twice the size shows that volume is increasing by 2 times and its pressure is kept the same.

Therefore,

`2V \propto 2T`

This means that the temperature of the gas will also become twice its initial temperature.

Thus, we can conclude that if a gas is pumped from a smaller container to a container that is twice the size, and its pressure is kept the same, then temperature of the gas increases twice.