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Solve the equation 2sin^2(x) = 1 for x ∈ [-π,π], expressing all solutions as exact values. please help its urgent !!
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Solve the equation 2sin^2(x) = 1 for x ∈ [-π,π], expressing all solutions as exact values. please help its urgent !!

User Buttonsrtoys
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4.1k points

1 Answer

6 votes

Answer:

2sin.2(x) sd s

Explanation:

User Mojtaba Haddadi
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