Question

A cat's displacement is 15 meters to the right in 7.0 seconds. If, at the start of the 7.0 seconds, the cat was moving at a velocity of 2.0 m/s left what was its final velocity?

Answer 1

6.3 m/s

Step-by-step explanation:

From the given information:

The displacement (x) = 15 m

time (t) = 7.0 s

initial velocity = -2.0 m/s (since it is moving in the opposite direction)

We need to determine the acceleration then find the final velocity.

By applying the kinematics equation:

`x = ut + (1)/(2)at^2`

`15 = (-2.0)(7.0) + (1)/(2)a(7.0)^2\\ \\ 15 = -14.0 + (49)/(2)a \\ \\ 29= 24.5a \\ \\ a= (29)/(24.5) \\ \\ a = 1.184 \ m/s^2`

Now, to determine the final velocity by using the equation:

v = u + at

v = -2 + 1.184(7.0)

v = 6.288 m/s

v ≅ 6.3 m/s