Question

Divided 29 into two parts so that the sum of the squares of the parts is 425 . Find the value of each part.​

Answer 1

Explanation:

Equations

x + y = 29

x^2 + y^2 = 425

Solution

y = 29 - x

x^2 + (29 - x)^2 = 425

x^2 + (841 - 58x + x^2 ) = 425

x^2 - 58x + x^2 + 841 - 425 = 0

2x^2 - 58x +416 = 0

a = 2

b = - 58

c = 416

You get two answers that look valid

2x^2 - 58x + 416 = 0

x^2 - 29x + 208 = 0 This factors

(x - 16)(x - 13) = 0

x = 16

y = 13

Now check it

16^2 + 13^2 = ? 425

256 + 169 = 425