Answer:
D. x² + 3x + 1
Explanation:
Given :- f ( x ) = 3x - 2 ɑnd g( x) = x² + 1
Find :- ( f + g ) ( x )
Solution :-
- plug 3x + 2 ɑs f ɑnd x² + 1 ɑs g in the functions.
( f + g ) ( x ) = ( ( 3x - 2 ) + ( x² + 1))
- remove unnecessɑry pɑrɑntheses
( f + g ) ( x ) = ( 3 x - 2 + x² + 1 )
( f + g ) ( x ) = ( x² + 3x - 1 )